Principles of Ecology Week 2
Prompt and submission available on Moodle.
For next week: See āWeek 3 Activitiesā on class website or Moodle (read peer-reviewed paper and listen to a podcast episode) . . .
Todayās lecture covers material from Chapter 1 of Gotelliās Primer of Ecology (link)
On Friday, we will begin to cover structured population growth, which is introduced in this video
Individuals of the same species living together
Individuals interact with one-another
e.g. mating, facilitating, competing
Photo by Jeffrey Hamilton on Unsplash
Photo by National Cancer Institute on Unsplash
For now, we will consider a āclosedā population
In a closed population, population size (\(N\)) only changes due to births and deaths
\[N_{t+1} = N_{t} + B - D\]
\[N_{t+1} - N_{t} = B-D\]
\[\Delta N = B-D\]
\[\frac{dN}{dt} = B-D\]
\[\frac{dN}{dt} = B-D\]
We need to know: What determines \(B\) and \(D\)?
Depends on the birth rate and mortality (death) rate:
\[B = bN\]
\[D = dN\]
\[\frac{dN}{dt} = B-D\]
\[B = bN \text{ and } D = dN\]
\[\frac{dN}{dt} = bN - dN\]
\[\frac{dN}{dt} = (b- d) N\]
\[\boxed{\frac{dN}{dt} = rN}\]
Populations grow when there are more births than deaths (\((b-d) > 0\); aka \(r > 0\))
Populations shrink when there are more deaths than births (\((b-d) < 0\); aka \(r < 0\))
The magnitude of \(r\) determines the rate of growth
Source: Wikimedia
Recall that the magnitude of \(r\) determines the rate of growth
What happens when \(r = 0\)?
\(r = 0\), when the rates of birth and death are equal to one another (\(b-d = 0\))
When this is true, the total number of births cancels out the total number of deaths, meaning the population size does not change.
\[\frac{dN}{dt} = rN = 0\]
This is the equilibrium state of the system.
Note that āequilibriumā doesnāt mean ānothing is changingā: there will be new births, and new deaths.
But they cancel each other, and the population size remains constant.
\[\frac{dN}{dt} = rN = 0\]
This is the equilibrium state of the system.
The exponential growth model has two equilibrium conditions. One is that \(r = 0\). What is the other?
We will be exploring the equilibrium conditions for many of the models we introduce through the semester, because it has been a central concept in ecology.
\[\frac{dN}{dt} = rN\]
\[N_t = N_0*e^{rt}\]
\[t_{\text{doubling}} = \frac{\text{ln}(2)}{r}\]
We can imagine that the dynamics of a population (i.e. how does population size change over time?) are strictly governed by two processes: births and deaths
We can express each of these in terms of the per-capita rates of birth and death: for a given unit of time, what is the per-capita rate of reproduction and of mortality?
The net population growth is governed by the difference in birth and death rate (\(r = b-d\))
This simplest model makes some unrealistic predictions, but some useful predictions
This simplest model also makes some assumptions
Key assumptions of the exponential growth model
No immigration or emigration (Closed population)
Constant birth and death rate (\(b\) and \(d\) donāt vary with \(N\))
No variation within population (all individuals have similar \(b\) and \(d\))
Continuous population growth without time lags
(e.g. no seasonality)
\[\frac{dN}{dt} = rN\]
Key assumptions of the exponential growth model
No immigration or emigration (Closed population)
Constant birth and death rate (\(b\) and \(d\) donāt vary with \(N\))
No variation within population (all individuals have similar \(b\) and \(d\))
Continuous population growth without time lags
(e.g. no seasonality)
Key assumptions of the exponential growth model
No immigration or emigration (Closed population)
Constant birth and death rate (\(b\) and \(d\) donāt vary with \(N\))
No variation within population (all individuals have similar \(b\) and \(d\))
Continuous population growth without time lags
(e.g. no seasonality)
Photo by Mike Erskine on Unsplash
Consider a bird species where each (female) adult lays \(10\text{ eggs}\). Only \(10\%\) of eggs successfully hatch into juveniles, and \(50\%\) of juveniles survive and mature into adults. Adults die after reproduction.
Photo by Mike Erskine on Unsplash
Consider a short-lived plant that lives for 6 years. Each year, only \(1\%\) of seeds survive and germinate into seedlings. (The other seeds are eaten by squirrels and jays). \(50\%\) of seedlings survive to a juvenile stage, and \(95\%\) of juveniles transition into reproductive sub-adults. Each sub-adult makes \(10\text{ seeds}\) per year, and \(95\%\) of sub-adults transition into fully-mature adults. Each mature adult makes \(450\text{ seeds}\) per year, and \(10\%\) of adults survive to a post-reproductive adult stage, which are incapable of making new seeds.
These transition diagrams can be represented mathematically as transition matrices.
For a population with \(n\) stages, we can capture the demographic transitions in an \(n\mathrm{-by-}n\) matrix.
Consider a bird species where each (female) adult lays \(10\text{ eggs}\). Only \(10\%\) of eggs successfully hatch into juveniles, and \(50\%\) of juveniles survive and mature into adults. Adults die after reproduction.
\[ \begin{bmatrix} ~ & ~ & ~ & ~ & ~& ~ & ~ \\ ~ & ~ & ~ & ~ & ~& ~ & ~ \\ ~ & ~ & ~ & ~ & ~& ~ & ~ \\ ~ & ~ & ~ & ~ & ~& ~ & ~ \\ ~ & ~ & ~ & ~ & ~& ~ & ~ \\ ~ & ~ & ~ & ~ & ~& ~ & ~ \end{bmatrix} \]
Consider a bird species where each (female) adult lays \(10\text{ eggs}\). Only \(10\%\) of eggs successfully hatch into juveniles, and \(50\%\) of juveniles survive and mature into adults. Adults die after reproduction.
\[ \begin{bmatrix} 0 & 0 & 10 \\ 0.1 & 0 & 0 \\ 0 & 0.5 & 0 \end{bmatrix} \]
Your turn
Consider a species of fish whose individuals live for 3 years (age classes 0, 1, 2, and 3). Newborn fish have a \(30\%\) survival rate to year 1; year 1 fish have a \(80\%\) survival rate to year 2; year 2 fish have a \(50\%\) survival rate to year 3; and all fish die in their third year.
Newborn fish are sexually immature and cannot give birth. Year 1 fish can give birth to \(1\) newborn per year; Year 2 fish can give birth to \(8\) newborns per year; and Year 3 fish can only give birth to \(0.5\) newborns per year.
Draw a transition diagram and write the transition matrix for this population.
\[ \begin{bmatrix} 0 & 1 & 8 & 0.5 \\ 0.3 & 0 & 0 & 0 \\ 0 & 0.8 & 0 & 0 \\ 0 & 0 & 0.5 & 0 \end{bmatrix} \]
\[ \begin{bmatrix} 0 & 1 & 8 & 0.5 \\ 0.3 & 0 & 0 & 0 \\ 0 & 0.8 & 0 & 0 \\ 0 & 0 & 0.5 & 0 \end{bmatrix} \]
At time \(t=0\), the population has \(52\) individuals in stage 0, \(10\) in stage 1, \(15\) in stage 2, and \(30\) in stage 3.
What is the expected distribution of individuals at \(t=1\)?
Matrix product of the transition matrix and the current distribution:
\[ \begin{bmatrix} 0 & 1 & 8 & 0.5 \\ 0.3 & 0 & 0 & 0 \\ 0 & 0.8 & 0 & 0 \\ 0 & 0 & 0.5 & 0 \end{bmatrix} \times \begin{bmatrix} 52 \\ 10 \\ 16 \\ 30 \end{bmatrix} \]
Matrix product of the transition matrix and the current distribution:
\[ \begin{bmatrix} 0 & 1 & 8 & 0.5 \\ 0.3 & 0 & 0 & 0 \\ 0 & 0.8 & 0 & 0 \\ 0 & 0 & 0.5 & 0 \end{bmatrix} \times \begin{bmatrix} 52 \\ 10 \\ 16 \\ 30 \end{bmatrix} = \begin{bmatrix} 153 \\ 15 \\ 8 \\ 8 \end{bmatrix} \]
For timestep \(2\):
\[ \begin{bmatrix} 0 & 1 & 8 & 0.5 \\ 0.3 & 0 & 0 & 0 \\ 0 & 0.8 & 0 & 0 \\ 0 & 0 & 0.5 & 0 \end{bmatrix} \times \begin{bmatrix} 153 \\ 15 \\ 8 \\ 8 \end{bmatrix} \]
For timestep \(2\):
\[ \begin{bmatrix} 0 & 1 & 8 & 0.5 \\ 0.3 & 0 & 0 & 0 \\ 0 & 0.8 & 0 & 0 \\ 0 & 0 & 0.5 & 0 \end{bmatrix} \times \begin{bmatrix} 153 \\ 15 \\ 8 \\ 8 \end{bmatrix} = \begin{bmatrix} 83 \\ 45.9 \\ 12 \\ 4 \end{bmatrix} \]
For timestep \(3\):
\[ \begin{bmatrix} 0 & 1 & 8 & 0.5 \\ 0.3 & 0 & 0 & 0 \\ 0 & 0.8 & 0 & 0 \\ 0 & 0 & 0.5 & 0 \end{bmatrix} \times \begin{bmatrix} 83 \\ 45.9 \\ 12 \\ 4 \end{bmatrix} = \dots \]
\[ \begin{bmatrix} 0 & 1 & 8 & 0.5 \\ 0.3 & 0 & 0 & 0 \\ 0 & 0.8 & 0 & 0 \\ 0 & 0 & 0.5 & 0 \end{bmatrix} \xrightarrow[]{\text{Eigenvalue}} 1.33 \]
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